Feb 16 • 13:35 UTC 🇮🇳 India Aaj Tak (Hindi)

The solar eclipse will peak at this time, and the 'Ring of Fire' will be visible in the sky

A solar eclipse, occurring on February 17, 2026, will feature a 'Ring of Fire' visible in India during its peak between 5:13 PM and 6:11 PM.

On February 17, 2026, India will witness its first solar eclipse of the year, marked as a significant celestial event in Hindu scriptures. This particular solar eclipse, which is set to occur during the Kumbha Rashi and Dhanishta Nakshatra, will be a 'ring-like' phenomenon rather than a total eclipse, earning it the nickname 'Ring of Fire' among astronomers. The eclipse will happen on the new moon day of Phalguna, making this event particularly noteworthy in Indian astronomical tradition.

The solar eclipse will take place from 3:26 PM to 7:57 PM Indian Standard Time, with a total duration of approximately 4 hours and 31 minutes. However, the most significant phase, when the 'Ring of Fire' will be visible, is expected to occur between 5:13 PM and 6:11 PM. During this hour, observers in India will be able to witness the peak of the eclipse, which is anticipated to be a breathtaking sight in the sky, adding excitement among amateur astronomers and citizens alike.

As a result of this solar eclipse, various discussions and predictions about its impact in India are expected. The occurrence of such an astronomical event often stirs interest in astrology and future implications according to Hindu beliefs, as eclipses are associated with various astrological interpretations. Hence, this eclipse will not only draw the attention of sky watchers but also of those interested in the cultural and spiritual significance attributed to solar eclipses.

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